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Ram Gopal Bhalla
Ram Gopal Bhalla
Asked: 3 years ago2022-11-11T09:28:49+05:30 2022-11-11T09:28:49+05:30In: General Awareness

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
Which statements are correct? (1) The expansion work for a gas into a vacuum is equal to zero. (2) `1` mole of a gas occupying `3` litre volume on expanding to `15` litre at constant pressure of `1atm` does expansion work `1.215 kJ`. (3) The maximum work done during expansion of `16gO_2` at `300K` from `5dm^3` to `25 dm^3` is `2.01 kJ`. (4) The `DeltaS` for `S to L` is almost negligible in comparision to `DeltaS` for `L to G`. (5) `DeltaS = 2.303 nR “log”(V_(2))/(V_(1)).` (at constant `T`)
A. 2,3,4,5
B. 1,2,3,4,5
C. 1,2
D. 4,5

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
Which statements are correct? (1) The expansion work for a gas into a vacuum is equal to zero. (2) `1` mole of a gas occupying `3` litre volume on expanding to `15` litre at constant pressure of `1atm` does expansion work `1.215 kJ`. (3) The maximum work done during expansion of `16gO_2` at `300K` from `5dm^3` to `25 dm^3` is `2.01 kJ`. (4) The `DeltaS` for `S to L` is almost negligible in comparision to `DeltaS` for `L to G`. (5) `DeltaS = 2.303 nR “log”(V_(2))/(V_(1)).` (at constant `T`)
A. 2,3,4,5
B. 1,2,3,4,5
C. 1,2
D. 4,5
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  1. e85ad
    2022-11-11T01:08:57+05:30Added an answer about 3 years ago

    Correct Answer – B
    (1) In free expansion `P_(ext) = 0 rarr w = 0`
    (2) `W = -1 [15-3] = -12lit-atm`
    `= -12 xx 101.3 J`
    (3) `W_(rev) = -2.303 xx (16)/(32) xx 8.314 xx 300 xx log.(25)/(5)`
    (4) `Delta S` for `L rarr G` is more
    (5) `(Delta S)_(T) = 2.303nR log.(v_(2))/(v_(1))`

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Shashank Kari
Shashank Kari
Asked: 3 years ago2022-11-10T19:28:14+05:30 2022-11-10T19:28:14+05:30In: General Awareness

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
A chemical change will definitely be spontaneous if:
A. `DeltaH=-ve, DeltaS=-ve` and low temperature
B. `DeltaH=+ve, DeltaS=-ve` and high temperature
C. `DeltaH=-ve, DeltaS=+ve` and any temperature
D. `DeltaH=+ve,DeltaS=+ve` and `TDeltaS lt DeltaH`

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
A chemical change will definitely be spontaneous if:
A. `DeltaH=-ve, DeltaS=-ve` and low temperature
B. `DeltaH=+ve, DeltaS=-ve` and high temperature
C. `DeltaH=-ve, DeltaS=+ve` and any temperature
D. `DeltaH=+ve,DeltaS=+ve` and `TDeltaS lt DeltaH`
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  1. 8b256
    2022-11-10T07:49:51+05:30Added an answer about 3 years ago

    Correct Answer – c
    `DeltaG=DeltaH-TDeltaS`
    `=-ve-Txx(+ve)=-ve`

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Chhaya Vaidya
Chhaya Vaidya
Asked: 3 years ago2022-11-08T05:26:20+05:30 2022-11-08T05:26:20+05:30In: General Awareness

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
Which statements are correct? (1) The expansion work for a gas into a vacuum is equal to zero. (2) `1` mole of a gas occupying `3` litre volume on expanding to `15` litre at constant pressure of `1atm` does expansion work `1.215 kJ`. (3) The maximum work done during expansion of `16gO_2` at `300K` from `5dm^3` to `25 dm^3` is `2.01 kJ`. (4) The `DeltaS` for `S to L` is almost negligible in comparision to `DeltaS` for `L to G`. (5) `DeltaS = 2.303 nR “log”(V_(2))/(V_(1)).` (at constant `T`)
A. `2,3,4,5`
B. `1,2,3,4,5`
C. `1,2`
D. `4,5`

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
Which statements are correct? (1) The expansion work for a gas into a vacuum is equal to zero. (2) `1` mole of a gas occupying `3` litre volume on expanding to `15` litre at constant pressure of `1atm` does expansion work `1.215 kJ`. (3) The maximum work done during expansion of `16gO_2` at `300K` from `5dm^3` to `25 dm^3` is `2.01 kJ`. (4) The `DeltaS` for `S to L` is almost negligible in comparision to `DeltaS` for `L to G`. (5) `DeltaS = 2.303 nR “log”(V_(2))/(V_(1)).` (at constant `T`)
A. `2,3,4,5`
B. `1,2,3,4,5`
C. `1,2`
D. `4,5`
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  1. 2c09f
    2022-11-08T00:33:56+05:30Added an answer about 3 years ago

    Correct Answer – b
    All are correct

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Yash Prasad Bali
Yash Prasad Bali
Asked: 3 years ago2022-11-06T16:49:03+05:30 2022-11-06T16:49:03+05:30In: General Awareness

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
The heat of vaporisation and heat of fusion of `H_2O` are `540 cal//g` and `80 cal//g`. This ratio of `(DeltaS_(vap.))/(DeltaS_(“fusion”))` for water is:
A. `6.75`
B. `9.23`
C. `4.94`
D. `0.2`

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
The heat of vaporisation and heat of fusion of `H_2O` are `540 cal//g` and `80 cal//g`. This ratio of `(DeltaS_(vap.))/(DeltaS_(“fusion”))` for water is:
A. `6.75`
B. `9.23`
C. `4.94`
D. `0.2`
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  1. 17b71
    2022-11-08T03:03:36+05:30Added an answer about 3 years ago

    Correct Answer – C
    `Delta_(vap)S = (540)/(373)`
    `Delta_(f)S = (80)/(273)`

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Sohail Chandra Bail
Sohail Chandra Bail
Asked: 3 years ago2022-11-06T02:05:58+05:30 2022-11-06T02:05:58+05:30In: General Awareness

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
`Ag_2O_((s)) to 2Ag_((s)) + 1/2 O_(2(g))` attains equilibrium at temperature…`K` is : (The `DeltaH` and `DeltaS` for the reaction are `30.5kJ mol^(-1)` and `66J mol^(-1) K^(-1)` )
A. `462.12`
B. 237
C. 373
D. 273

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
`Ag_2O_((s)) to 2Ag_((s)) + 1/2 O_(2(g))` attains equilibrium at temperature…`K` is : (The `DeltaH` and `DeltaS` for the reaction are `30.5kJ mol^(-1)` and `66J mol^(-1) K^(-1)` )
A. `462.12`
B. 237
C. 373
D. 273
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  1. 1c6fc
    2022-10-31T10:25:08+05:30Added an answer about 3 years ago

    Correct Answer – A
    At eq, `Delta G = 0 rArr Delta H – T Delta S = 0`
    `T = (Delta H)/(Delta S)`

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Nikita Chatterjee
Nikita Chatterjee
Asked: 3 years ago2022-11-05T14:15:03+05:30 2022-11-05T14:15:03+05:30In: General Awareness

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
A chemical change will definitely be spontaneous if:
A. `Delta H = -ve, Delta S = -ve` and low temperature
B. `Delta H = +ve, Delta S = -ve` and high temperature
C. `Delta H = -ve, Delta S = +ve` and any temperature
D. `Delta H = +ve, Delta S = +ve` and `T Delta S lt Delta H`

Work done by the system in isothermal reversible process is `w_(rev.)= -2.303 nRT “log”(V_(2))/(V_(1))`. Also in case of adiabatic reversible process work done by the system is given by: `w_(rev.) = (nR)/(gamma -1) [T_2 – T_1]`. During expansion disorder increases and the increase in disorder is expressed in terms of change in entropy `DeltaS = q_(rev.)/T`. The entropy changes also occurs during transformation of one state to other end expressed as `DeltaS = DeltaH/T`. Both entropy and enthalpy changes obtained for a process were taken as a measure of spontaniety of process but finally it was recommended that decrease in free energy is responsible for spontaniety and `DeltaG=DeltaH – T DeltaS`.
A chemical change will definitely be spontaneous if:
A. `Delta H = -ve, Delta S = -ve` and low temperature
B. `Delta H = +ve, Delta S = -ve` and high temperature
C. `Delta H = -ve, Delta S = +ve` and any temperature
D. `Delta H = +ve, Delta S = +ve` and `T Delta S lt Delta H`
Parabola
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  1. 0bf70
    2022-10-29T20:20:03+05:30Added an answer about 3 years ago

    Correct Answer – C
    Conditions for spontaniety

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