Correct Answer – A::B::C
For a cyclic process `dU = 0`
`:. q = Delta U + (-w) ” ” q = -w`
Also, w = area covered by sphere
`= pi r^(2)=pi xx[((V_(2)-V_(1)))/(2)]^(2) = (pi xx (20)^(2))/(2^(2)) = 100 xx 3.14 = 3.14 J`

For a cyclic process, `dU = 0`
`:. Q = DeltaU +(-w) rArr q =- w`
Also, `w =` Area covered by sphere
`= pir^(2) = pi xx [((V_(2)-V_(1)))/(2)]^(2)`
`= (pixx(20)^(2))/(2^(2))`
`= 100 pi = 100 xx 3.14 = 314 J`