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Yadu Ratan Halder
Asked: 2022-11-11T19:32:46+05:30 In:

Which one among the following pairs of ions cannot be separated by `H_(2)S` in dilute hydrochloric acid ?
A. `Bi^(3+) , Sn^(4+)`
B. `Al^(3+) , Hg^(2+)`
C. `Zn^(2+) , Cu^(2+)`
D. `Ni^(2+) , Cu^(2+)`

Which one among the following pairs of ions cannot be separated by `H_(2)S` in dilute hydrochloric acid ?
A. `Bi^(3+) , Sn^(4+)`
B. `Al^(3+) , Hg^(2+)`
C. `Zn^(2+) , Cu^(2+)`
D. `Ni^(2+) , Cu^(2+)`
Parabola
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  1. Correct Answer – A
    Both belong to same group i.e. `II^(nd)` group and their `K_(SP)` values are low, so both are precipitated according to the following reactions.
    `{:(2Bi^(3+),+,3S^(2-),to,Bi_(2)S_(3),darr,(“black”)),(Sn^(4+),+,2S^(2-),to,SnS_(2),darr,(“yellow”)):}`

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Pinky Pranay Contractor
Asked: 2022-11-06T20:13:37+05:30 In:

Which one among the following pairs of ions cannot be separated by `H_(2)S` in dilute HCl ?
A. `Bi^(3+),Sn^(4+)`
B. `Al^(3+),Hg^(2+)`
C. `Zn^(2+),Cu^(2+)`
D. `Ni^(2+),Cu^(2+)`

Which one among the following pairs of ions cannot be separated by `H_(2)S` in dilute HCl ?
A. `Bi^(3+),Sn^(4+)`
B. `Al^(3+),Hg^(2+)`
C. `Zn^(2+),Cu^(2+)`
D. `Ni^(2+),Cu^(2+)`
Parabola
Leave an answer

Leave an answer

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1 Answer

  1. Correct Answer – 1

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