When the temperature of a rod increases from t to `r+Delta t`, its moment of inertia increases from I to `I+Delta I`. If `alpha` is the value of `Delta I//I` is
A. `Delta t//t`
B. `Delta t//t`
C. `alpha Delta t`
D. `2alpha Delta t`
A. `Delta t//t`
B. `Delta t//t`
C. `alpha Delta t`
D. `2alpha Delta t`
Correct Answer – D
from `I = MR^(2), (DeltaI)/(I) = 2 xx (DeltaR)/(R), (DeltaI)/(I) = 2alphaDeltat`