When ammonia is heated with cupric oxide, a molecule of ammonia will
A. Gain 3 electrous
B. Lose 3 electrons
C. Gain 2 electrons
D. Lose 2 electrons
A. Gain 3 electrous
B. Lose 3 electrons
C. Gain 2 electrons
D. Lose 2 electrons
Correct Answer – B
`2NH_(3)+3CuO to N_(2)+H_(2)O +3Cu`
`underset(“( O.S.=-3)”)(2NH_(3)) to underset(“(O.S.=0)”)(N_(2))`
Thus each N atoms (or each `NH_(3)` molecule) loses 3 electrons