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Nakul Lal Gupta
Asked: 2022-11-10T03:19:04+05:30 In:

When a liquid that is immiscible with water was steam distilled at `952^(@)C` at a total pressure of `748` torr, the distillate contained `1.25g` of the liquid per gram of water. The vapour pressure of water is `648` torr at `95.2^(@)C`. What is the molar mass of liquid?
A. `7.975 g//”mol”`
B. `166 g//”mol”`
C. `145.8g//”mol”`
D. None of these

When a liquid that is immiscible with water was steam distilled at `952^(@)C` at a total pressure of `748` torr, the distillate contained `1.25g` of the liquid per gram of water. The vapour pressure of water is `648` torr at `95.2^(@)C`. What is the molar mass of liquid?
A. `7.975 g//”mol”`
B. `166 g//”mol”`
C. `145.8g//”mol”`
D. None of these
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1 Answer

  1. Correct Answer – A::B::C::D
    For two immischible liquid ,
    `P_(A)^(@)=P_(“total”)-P_(H_(2^(O)))^(@)=748-648rArr100`
    `(W_(A))/(W_(B))=(P_(A)^(@)M_(A))/(P_(B)^(@)M_(B)) , M_(A)=(1.25)/(1)xx(648xx18)/(100)rArr145.8`

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