Home/ Questions/Q 460600
Next
In Process
Sohail Neerendra Thomas
Asked: 2022-11-10T08:20:55+05:30 In:

When `250 mg` of eugenol is added to `100 g` of camphor `(k_(f)=39.7″ molality”^(-1))`, it lowered the freezing point by `0.62^(@)C` . The molar of eugenol is `:`
A. `1.6xx10^(2) g//mol`
B. `1.6xx10^(4)g//mol`
C. `1.6xx10^(3)g//mol`
D. `200g//mol`

When `250 mg` of eugenol is added to `100 g` of camphor `(k_(f)=39.7″ molality”^(-1))`, it lowered the freezing point by `0.62^(@)C` . The molar of eugenol is `:`
A. `1.6xx10^(2) g//mol`
B. `1.6xx10^(4)g//mol`
C. `1.6xx10^(3)g//mol`
D. `200g//mol`
Parabola
Leave an answer

Leave an answer

Browse

1 Answer

  1. Correct Answer – 1
    `0.62=(250xx10^(-3))/(Mxx100)xx1000xx39.7xx1`
    `M=160` or `1.6xx10^(2)g//mol`

    • 0