What weight of `HNO_(3)` is needed to convert `5g` of iodine into iodic acid according to the reaction,
`I_(2)+HNO_(3)rarrHIO_(3)+NO_(2)+H_(2)O`
A. `12.4 g`
B. `24.8 g`
C. `0.248 g`
D. `49.6 g`
`I_(2)+HNO_(3)rarrHIO_(3)+NO_(2)+H_(2)O`
A. `12.4 g`
B. `24.8 g`
C. `0.248 g`
D. `49.6 g`
Correct Answer – A
`{:(1e,+,N^(5+),rarr,N^(4+),),(,,I_(2)^(0),rarr,2I^(5+),+10e),(,,,,,):}`
Meq. Of `HNO_(3)=` Meg. Of `I_(2)`
`(w)/(63//1)xx1000xx=(5)/(254//10)xx1000`
`w=12.4g`