What is the general solution of the equation: `tan^2 theta + 2sqrt3 tan theta = 1?`

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Correct Answer – `theta=n pi + pi/12, n in Z or theta = mpi – (5pi)/12; m in Z`

`tan^(2) theta + 2 sqrt3 tan theta = 1`

or `(tan theta + sqrt3)^(2) = 4`

or `tan theta = 2 – sqrt3 or -2 – sqrt3`

or `tan theta = tan 15^(@), – tan 75^(@)`

`= “tan”(pi)/(12), tan (-(5pi)/(12))`

From `tan theta = “tan” (pi)/(12)`, we get

`theta = n pi + (pi)/(12), n in Z`

From `tan theta = tan (-(5pi)/(12))`, we get

`theta = m pi – (5pi)/(12), m in Z`