what is apparent weight during take off an astronaut whose actual weight is 750N
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Firstly, the mass of the astronaut is const. and before the take off his weight was , F = m × a . Then , as the rocket accelerates the acceleration of the astronaut becomes 5g + 1g = 6g . Hence, we can now simply find his apparent weight from that formula • F = m × a like that , F = 750N × 6g = 4500g