Use Euclid algorithm to find the hcfof 4052 and 12576
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This question is wrong…. I think ???
12576>4052 by euclid division alogrinthm 12576=4052*3 +420 4052=420*9+272 420=272*1+148 272=148*1+124 148=124*1+24 124=24*5+4 24=4*6+0 as the process stops . so our HCF is 4