Two taps A and B can fill an overhead tank in 10 hours and 15 hours respectively. Both the taps are opened for 4 hours and then B is turned off. How much time will A take to fill the remaining tank?
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The given details are,
Tap A can fill the tank in = 10 hours
Tap A can fill the tank in 1 hour = 1/10
Tap B can fill the tank in = 15 hours
Tap B can fill the tank in 1 hour = 1/15
Both taps together can fill the tank in 1 hour = 1/10 + 1/15
= (3+2)/30 = 5/30
= 1/6
Both taps together can fill the tank in 4 hours = 4 × 1/6 = 2/3
Remaining tank to be filled = 1 – 2/3
= (3-2)/3
= 1/3
∴ Time taken by A to fill the remaining tank = (1/3)/(1/10)
= 10/3
= 3 1/3 hours