Two masses 10kg and 20 kg are connected by a massless spring. A force of 200 N acts on 20 kg mass. At the instant when the 10 kg mass has an acceleration 12 ms-2, what will be the energy stored in the spring? k = 2400 M/m
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We know that F = ma
F = 10 × 12 = 120 N
But F = k x = 2400 x = 120 n
∴ x = \(\frac{1}{20}\)
∴ energy stored in spring
E = \(\frac{1}{2}\) kx2 = \(\frac{1}{2}\)× 2400 × \((\frac{1}{2})^2 = 3J\).