Two identical uniform rods of length `l` are joined to from `L` shaped frame, as shown is Fig. Locate the centre of mass of the frame.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Let `m` be the mass of each rod. In Fig. `B` is taken as origin. `BC` is X-axis and `BA` is Y-axis. As the rods are uniform, their individual centre of mass must be lying at there respective centres, say `P` and `Q`. Thus the system is equivalent to two point masses `m` each, at `P (l//2,0)` and `Q(0,l//2)`
`:. x_(cm) = (mxxl//2 + m xx0)/(m+m) = l//4`
and `y_(cm) = (m xx 0 + m xx l//2)/(m + m) = l//4`
Hence centre of mass of the system is at `O(l//4 , l//4)`.