Two identical sounds A and B reach a point in the same phase. The resultant sound is C. The loudness of C is n dB higher than the loudness of A. The value of n is
(a) 2
(b) 3
(c) 4
(d) 6
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Correct Answer is: (d) 6
Let a = amplitude due to A and B, individually.
Loudness due to A = IA = ka2 (k = constant)
Loudness due to A + B = IC = k(2a)2 = 4IA.
n = 10 log10 (IC/IA) = 10 log10 4 = 10 x 0.6 = 6.