Two identical rods of same metal are first waleded in series and then in parallel are maintained at same temperature difference then the ratio of heats conducted in same time is .
A. `1 :1`
B. `1:2`
C. `1:4`
D. `1:3`
A. `1 :1`
B. `1:2`
C. `1:4`
D. `1:3`
Correct Answer – C
`Q=(KA(Delta theta)t)/(l)`
`(Q_(1))/(Q_(2))=(K_(s)A(Delta theta)t)/(2l)xx(l)/(K_(p)2A(DeltaA)t)(“here “K_(s)=K_(p))`