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Two dice are thrown simultaneously. The probability of getting a pair of sixes is
A. \(\frac{1}{36}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{6}\)
D. none of these
Two dice are thrown simultaneously. The probability of getting a pair of sixes is
A. \(\frac{1}{36}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{6}\)
D. none of these
Correct Answer – Option 3 : 1/12
Given:
Two dice are thrown simultaneously
Formula Used:
P(E) = n(E)/n(S)
Where,
n(E) = Number of favourable events
n(S) = Number of possible outcomes
Calculation:
When two dice throw simultaneously, then total possible outcomes
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2),…………………………., (2, 6)
……………………………………………………
……………………………………………………
(6, 1), (6, 2), …………………………..(6, 6)
Number of possible outcomes n(S) = 6 × 6
⇒ 36
Number of favourable events n(E) = {(4,6), (6,4), (5,5)} = 3
⇒ n(E) = 3
Required probability of getting a total of 10
P(E) = 3/36
⇒ 1/12
∴ The probability of getting a total of 10 is 1/12.