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Rita Somnath Shanker
Rita Somnath Shanker
Asked: 3 years ago2022-11-10T01:31:04+05:30 2022-11-10T01:31:04+05:30In: Mensuration

Two concentric circles with radii p cm and (p+ 2) cm are drawn on a paper. The difference between their areas is 44 sq. cm What is the value of p?(Take π  = \(\frac{22}{7}\))
1. 1.5
2. 5
3. 6
4. 2.5

Two concentric circles with radii p cm and (p+ 2) cm are drawn on a paper. The difference between their areas is 44 sq. cm What is the value of p?(Take π  = \(\frac{22}{7}\))
1. 1.5
2. 5
3. 6
4. 2.5
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  1. b5950
    2022-11-10T22:20:25+05:30Added an answer about 3 years ago

    Correct Answer – Option 4 : 2.5

    Given:

    difference between areas is 44 sq. cm 

    radii = p cm and (p+2) cm

    Formula Used:

    Area of Circle = π.r2

    Calculation:

    π.R2 – π.r2 = 44

    ⇒π(R2 – r2) = 44

    ⇒22/7{(R + r)(R – r)} = 44

    ⇒{(p+2+p)(p+2-p)} = 14

    ⇒(2p + 2)2 = 14 

    ⇒2p+ 2 = 7

    ⇒2p = 5

    ∴ The value of p is 2.5

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Aayushi Shanker
Aayushi Shanker
Asked: 3 years ago2022-11-08T14:04:37+05:30 2022-11-08T14:04:37+05:30In: Mensuration

Two concentric circles with radii p cm and (p + 2) cm are drawn on a paper. The difference between their areas is 44 sq.cm What is the value of p?(Take π  = 22/7)
1. 1.5
2. 5
3. 6
4. 2.5

Two concentric circles with radii p cm and (p + 2) cm are drawn on a paper. The difference between their areas is 44 sq.cm What is the value of p?(Take π  = 22/7)
1. 1.5
2. 5
3. 6
4. 2.5
Spectroscopy
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  1. 72016
    2022-11-11T08:54:04+05:30Added an answer about 3 years ago

    Correct Answer – Option 4 : 2.5

    Given:

    Radius of First circle = p cm

    Radius of Second circle = (p + 2) cm

    Difference between areas of both the circles = 44 cm2

    Formula Used:

    Area of circle = π(Radius)2

    (a + b)2 = a2 + b2 + 2ab

    Calculation:

    Area of First circle = π(p cm)2

    ⇒ πp2 cm2

    Area of Second circle = π{(p + 2) cm}2

    ⇒ π(p2 + 4p + 4) cm2

    Difference between area of both the circles = π(p2 + 4p + 4) – πp2 

    ⇒ π(p2 + 4p + 4 – p2) = 44

    ⇒ 4π(p + 1) = 44

    ⇒ 4 × (22/7)(p + 1) = 44

    ⇒ p + 1 = (44 × 7)/88

    ⇒ p + 1 = 7/2

    ⇒ p = 7/2 – 1

    ⇒ p = 5/2

    ⇒ p = 2.5

    ∴ The value of p is 2.5

     

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