Theorem 10.1 and 10.2 solution
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Theorem no. 10.2In triangle PQO and PROOQ=OR (radius of same circle)Op=op (common)Angle Q = angleR (each 90)∆PQO conqurent ∆PROPQ=PR (cpct)