the work done against force of friction is
A. 8.7 J
B. 10.7 J
C. 7.8 J
D. 12.7 J
A. 8.7 J
B. 10.7 J
C. 7.8 J
D. 12.7 J
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Correct Answer – A
Work against friction is `W_f=fd=muNd=mumgcosthetad ” ” (therefore N=mgcos theta)`
`=0.1xx1 kg xx 10 m s^(-2) xx cos 30^@ xx 10 m`
=8.7 J