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Raju Chandra Gour
Asked: 2022-11-10T03:11:31+05:30 In:

The weighted means of of first n natural numbers whose weights are equal to the squares of corresponding numbers is
A. `(n+1)/(2)`
B. `(3n(n+1))/(2(2n+1))`
C. `((n+1)(2n+1))/(6)`
D. `(n(n+1))/(2)`

The weighted means of of first n natural numbers whose weights are equal to the squares of corresponding numbers is
A. `(n+1)/(2)`
B. `(3n(n+1))/(2(2n+1))`
C. `((n+1)(2n+1))/(6)`
D. `(n(n+1))/(2)`
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1 Answer

  1. Correct Answer – B
    Weighted mean `=(1.1^(2)+2.2^(2)+..+n.n^(2))/(1^(2)+2^(2)+..+n^(2))`
    `=(sumn^(3))/(sumn^(2))=((n(n+1))/(2)(n(n+1))/(2))/((n(n+1)(2n+1))/(6))=(3n(n+1))/(2(2n+1))`

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