The turbine pits at Niagra Falls are 50m deep. The average horse power develop is 5000. If the efficiency of the generator `85%` , how much water passes through the turbine per minute ? Take `g=10m//s^(2)`.
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Here, `h=50m, H.P.=5000, eta=85%`,
`m_(2)` useful power `=5000HP=5000xx746 wat t`.
Total power generated
`=(5000xx746)/(85%)=(500xx746xx100)/(85)`
`=4.388xx10^(6) wat t`
Total work done by the falling water in 1 minute
`mgxxh=4.388xx10^(6)xx60J`
`m=(4.388xx10^(6)xx60)/(gh)=(4.388xx10^(6)xx60)/(10xx50)`
`m=5.39xx10^(5)kg`