The sun radiates energy at the rate of `4xx10^(26)` joule `sec^(-1)`. If the energy of fusion process
`4 ._(1)^(1)H rarr ._(2)^(4)He + 2 ._(1)^(0)e`
is `27MeV`, calculated amount of hydrogen atoms that would be consumed per day for the given process.
`4 ._(1)^(1)H rarr ._(2)^(4)He + 2 ._(1)^(0)e`
is `27MeV`, calculated amount of hydrogen atoms that would be consumed per day for the given process.
Correct Answer – `53.16xx10^(18)g`