The sum of two rational numbers is (-3/8). If one of them is (3/16), find the other.
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Let the required number be x. Then,
= (3/16) + x = (-3/8)
By sending (3/16) from left hand side to the right hand side it changes to – (3/16)
x = (-3/8) – (3/16)
LCM of 8 and 16 is 16
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
= [(-3×2)/ (8×2)] = (-6/16)
= [(3×1)/ (16×1)] = (3/16)
Then,
= (-6/16) – (3/16)
= (-6-3)/16
= (-9/16)
Hence the required number is (-9/16)