The sum of 2 digits number and the number forward by interchange the digits is 132
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Let the two digit no. be 10x + yand the no. when reversed be 10y + xaccording to the question :10x + y + 10y + x = 13211x + 11y = 132taking 11 common11(x + y ) = 132x + y = 12 ———– 1)lets do the second partNow,10x + y + 12 = 5(x + y)10x + y + 12 = 5x + 5y5x + 12 = 4y4y – 5x = 12 —— 2)substituting y = 12 – x in equation 2)4( 12 – x ) – 5x = 1248 – 4x – 5x = 1248 – 12 = 9×36 = 9xx = 4x + y = 124 + y = 12y = 8so the no. is 48