The spring constants of two springs of same length are `k_(1)` and `k_(2)` as shown in figure. If an object of mass m is suspended and set in vibration , the period will be

A. `2pisqrt((mk_(1))/(k_(2)))`
B. `2pisqrt((m)/(k_(1)k_(2)))`
C. `2pisqrt((m)/(k_(1)-k_(2)))`
D. `2pisqrt(m//(k_(1)+k_(2)))`

A. `2pisqrt((mk_(1))/(k_(2)))`
B. `2pisqrt((m)/(k_(1)k_(2)))`
C. `2pisqrt((m)/(k_(1)-k_(2)))`
D. `2pisqrt(m//(k_(1)+k_(2)))`
Correct Answer – D
(d) The springs are corrected in parallel. So, the efffective force constant will be `k_(e)=k_(1)+k_(2)`
`therefore T=2pisqrt((m)/(k_(e)))=2pisqrt((m)/(k_(1)+k_(2))`