The scale on a steel on a steel meter stick is calibrated at `15^@ C`. What is the error in the reading of `60 cm` at `27^@C` ? `alpha_(steel) =1.2 xx 10^-5 (.^@ C)^-1`.
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Correct Answer – C::D
The error in the reading will be
`Deltal = (“scale reading”) (alpha)(Delta T)`
`= (60) (1.2 xx 10^-5)(27^@ – 15^@)`
= `0.00864 cm`.