The resistance R=VI where V=100V+/-5V and I=10A+/-0.2A.find the percentage error in R.
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Here,\xa0{tex}V = 100 \\pm 5V{/tex}and\xa0{tex}I = 10 \\pm 0.2A{/tex}Expressing limits of error as percentage error, we have{tex}V = 100V \\pm \\frac{5}{{100}} \\times 100 = 100V \\pm 5\\% {/tex}{tex}I = 10A \\pm \\frac{{0.2}}{{100}} \\times 100 = 10A \\pm 2\\% {/tex}Now,{tex}R = \\frac{V}{I}{/tex}{tex}\\therefore{/tex}% error in R=%error in V + % error in I=5%+2%=7%{tex}\\therefore{/tex}% error in R=7%\xa0