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Faraz Dev Kata
Faraz Dev Kata
Asked: 3 years ago2022-11-10T19:16:34+05:30 2022-11-10T19:16:34+05:30In: General Awareness

The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to the
A. `x` -axis
B. `y`-axis
C. `z`-axis
D. Line at equal angles to all the three axes

The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to the
A. `x` -axis
B. `y`-axis
C. `z`-axis
D. Line at equal angles to all the three axes
Parabola
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  1. f87d6
    2022-11-07T14:34:17+05:30Added an answer about 3 years ago

    Correct Answer – A

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Jobin Batta
Jobin Batta
Asked: 3 years ago2022-11-04T18:45:15+05:30 2022-11-04T18:45:15+05:30In: General Awareness

The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to the
A. `x`-axis
B. `y`-axis
C. `z`-axis
D. line at equal angles to all the three axes

The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to the
A. `x`-axis
B. `y`-axis
C. `z`-axis
D. line at equal angles to all the three axes
Parabola
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  1. abeff
    2022-11-10T04:14:19+05:30Added an answer about 3 years ago

    `vecl=vecrxxvecp=|[hati,hatj,hatk],[1,2,-1],[3,4,-2]|=-hatj-2hatk`

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Mohit Sagar
Mohit Sagar
Asked: 3 years ago2022-10-31T18:01:45+05:30 2022-10-31T18:01:45+05:30In: General Awareness

The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to the
A. x-axis
B. y-axis
C. z-axis
D. yz-plane

The position of a particle is given by `vecr=(hati+2hatj-hatk)` and momentum `vecp=(3hati+4hatj-2hatk)`. The angular momentum is perpendicular to the
A. x-axis
B. y-axis
C. z-axis
D. yz-plane
Parabola
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  1. 01e56
    2022-10-31T03:50:11+05:30Added an answer about 3 years ago

    Correct Answer – a
    Here, `vecr=hati+2hatj-hatk, vecp=3hati+4hatj-2hatk`
    `vecL= vecr xx vecp= |{:[hati, hatj, hatk],[1,2,-1],[3,4,-2]:}|=hati(-4+4)+hatj(-3+2)+hatk(4-6)=0hati-1hatj-2hatk`
    `vecL` has component along `-y` axis and `-z` axis but it has no component along the x-axis. The angular momentum `vecL` is in yz-plane. i.e., perpendicular to x-axis.

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