A. `0`, `+1` and `-2`
B. `+2`, `+1` and `-2`
C. `0`, `+1` and `+2`
D. `-2`, `+1` and `-2`
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Correct Answer – A
`{:(S_(8):axx8=0,,:. a=0,,,),(S_(2)F_(2):axx2+2xx(-1)=0,,:. a=+1,,,),(H_(2)S:2xx1+a=0,,:. a=-2,,,):}`
Correct Answer – A
`S_(8)`: Oxidation numbers of `S=0`
`S_(2)F_(2): 2x-2=0impliesx=1,` Oxidation number of `S=1`
`H_(2)S:2+x=0impliesx=2` , Oxidation number of `S= -2`
Correct Answer – A
In `S_(8)`, oxidation number of `S` is 0, elemental state.
In `S_(2)F_(2), F` is in `-1` oxidation state, hence S is in `-2` oxidation state.
In `H_(2)S, H` is in `+1` oxidation state, hence S is in `-2` oxidation state.
Correct Answer – A
`overset(*)(S_(8))=0` `overset(*)(S_(2))F_(2)=+1` `H_(2)overset(*)(S)= -2`