The number of electrons transferred (lost and gained ) during the reactiong `Fe + H_(2)O rarr Fe_3 O_4 + H_2` is .
A. `8`
B. `6`
C. `4`
D. `2`
A. `8`
B. `6`
C. `4`
D. `2`
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Correct Answer – A
`overset(0)(F)e+overset(+1)(H_(2))overset(-2)(O)rarr overset(+8//3)(Fe_(3))overset(-2)(O_(4))+overset(0)(H_(2))`
Oxidation half-reaction
`3overset(0)(F)e rarroverset(+8//3)(Fe_(3))O_(4)+8e^(-)`
Reduction half-reaction
`overset(+1)(H_(2))overset(-2)(O)+2e^(-) rarr overset(0)(H_(2))`
`4H_(2)O+8e^(-) rarr 4H_(2)`
Thus, eight electrons are transferred during the reaction