The normal boiling point of toluene is `110.7^(@)C` and its boiling point elevation constant `3.32 ” K kg mol”^(-1)`. The enthalpy of vaporization of toluene is nearly :
A. `”17 kJ mol”^(-1)`
B. `”21 kJ mol”^(-1)`
C. `”51 kJ mol”^(-1)`
D. `”68 kJ mol”^(-1)`
A. `”17 kJ mol”^(-1)`
B. `”21 kJ mol”^(-1)`
C. `”51 kJ mol”^(-1)`
D. `”68 kJ mol”^(-1)`
Correct Answer – B
`K_(b)=(RT_(0)^(2))/(1000L),3.32=((8.314xx10^(-3))xx(383.7)^(2))/(1000xxL)`
`L=0.368kJ//g`
Latent heat per mol `= 0.368 xx` molar mass of acetone
`= 0.368xx58=21.344″ kJ mol”^(-1)`].