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Ram Gopal Ajinkya Sabharwal
Asked: 2022-11-04T11:37:43+05:30 In:

The motion of a particle varies with time according to the relation `y=a (sinomegat + cos omegat)` ,then
A. the motion is oscillatory but not SHM
B. the motion is SHM with amplitude a
C. the motion is SHM with amplitude `sqrt2a`
D. None of these

The motion of a particle varies with time according to the relation `y=a (sinomegat + cos omegat)` ,then
A. the motion is oscillatory but not SHM
B. the motion is SHM with amplitude a
C. the motion is SHM with amplitude `sqrt2a`
D. None of these
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1 Answer

  1. Correct Answer – C
    `y=a sin omegat+a cos omegat+a sin(omegat+(pi)/(2))`
    The resultant motion is SHM but resultant amplitude is
    `A=sqrt(a^(2)+a^(2)+2a^(2)cos .(pi)/(2))=sqrt(2a)`

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