the lenths of the diagonals of a rombes are 30cm and 40cm. find side of the rombas
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Let ABCD is a rhombus\xa0with AC and BD as its diagonals.We know that the diagonals of a rhombus bisect each other at right angles.Let O be the intersecting point of both the diagonals.Let AC = 30 cm and BD = 40 cmOA = AC/2OA = 30/2= 15 cmOB = BD/12OB = 40/2= 20 cmIn right\xa0{tex}\\triangle{/tex}AOB by pythagoras theorem we haveAB2 = OA2 + OB2= (15)2 + (20)2= 225 + 400= 625AB = 25 cmHence, each side of the rhombus is length 25 cm.