The length and breadth of a metal sheet are `1.124m and 0.002m` respectively .The area of the sheet up in four currect significant figure is
A. `9.3782m^(3)`
B. `9.37m^(3)`
C. `9.378248 m^(3)`
D. `9.378m^(3)`
A. `9.3782m^(3)`
B. `9.37m^(3)`
C. `9.378248 m^(3)`
D. `9.378m^(3)`
Correct Answer – d
According to rule of significant figures
●any zeros that are between non – zero also consider significant
● all none -zero digit significant.
Hence , breadth of metel `b = 3.002m` has four significant figure
`:.` Length of metal `= 3.124 m` has four significant figures.
Since length and breadth have four significant therefore
`”Area” = “length” xx “breadth”`
`= 3.124 xx 3.002 = 9.378248`
will also have four significant figures.
Hence, `”area” = 9.378m^(2)`