The `K_(alpha)` X-ray emission line of lungsten accurs at `lambda = 0.021 nm`. What is the energy difference between `K`and `L` levels in the atom?
A. `0.51 MeV`
B. `1.2 MeV`
C. `59 keV`
D. `13.6 eV`
A. `0.51 MeV`
B. `1.2 MeV`
C. `59 keV`
D. `13.6 eV`
Correct Answer – C
`DeltaE=1242/(lambda(nm))eV=1242/0.021=59142 eV~= 59KeV`