The ionization energy of hydrogen in excited state is `+0.85 eV`. What will be the energy of the photon emitted when it returns to the ground state?
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Energy of H-atom in the ground state `= – 13.6 eV`
Ionization energy of hydrogen in excited state equal to `+0.85 eV` means
Energy of H-atom in the excited state `= – 0.85 eV`
`:.` Energy emitted `= -0.85 eV – (-1.6 eV) = 12.75 eV`