The freezing point of a solution containing `50 cm^(3)` of ethylene glycol in `50 g` of water is found to be `-34^(@)C`. Assuming ideal behaviour, Calculate the density of ethylene glycol `(K_(f)` for water = `1.86 K kg mol^(-1)`).
Correct Answer – A
`DeltaT=K_(f)xx(wxx1000)/(mxxW)`
`34=1.86xx(wxx1000)/(62xx50)`
`w=56.66g`
`V=(w)/(d)`
`50=(56.66)/(d)`
`d=1.13g//cm^(3)`
`DeltaT = (K_(f) xx W_(f) xx 1000)/(Mw_(2) xx W_(1))`
`34 = 1.86xx(W_(2) xx 1000)/(62 xx50)`
`W_(2) = 56.66 g`
`(V) = (W_(2))/(d)`
`(50) = (56.66)/(d)`
` d = 1.13 g cm^(-3)`.