The focal length of the objectives and the eyepiece of an astronomical telescope are `16cm`and`2cm` respectively .A planet is viewed with its help ,then

A. The angular magnification of the planet is`-800`

B. The image of the planet is inverted

C. the distance between the objectives and the eye piece of`16.02`

D. All the above

A. The angular magnification of the planet is`-800`

B. The image of the planet is inverted

C. the distance between the objectives and the eye piece of`16.02`

D. All the above

Correct Answer – 4

`therefore` Distance between objectives and eyepiece

`=f_(0)+f_(e)=16.02m`

Angular magnification`M=-(f_(0))/(f_(e))`

or`M=(-16)/(0.02)=-800`

The image formed by a telescope is always inverted.