The equation of straight line passing through the point (1, -2) and parallel to the line y = 5x – 2 is
1. \(\rm (y + 2) = 5 (x +1)\)
2. \(\rm (y + 2) = 5 (x -1)\)
3. \(\rm (y + 2) = \frac 1 5 (x -1)\)
4. None of these
1. \(\rm (y + 2) = 5 (x +1)\)
2. \(\rm (y + 2) = 5 (x -1)\)
3. \(\rm (y + 2) = \frac 1 5 (x -1)\)
4. None of these
Correct Answer – Option 2 : \(\rm (y + 2) = 5 (x -1)\)
Concept:
The equation of the straight line passing through the point \(\rm (x_1, y_1)\) is given by,
\(\rm (y – y_1) = m (x -x_1)\), where m is the slope of the line.
Note: The slope of the parallel lines are equal
Calculations:
The equation of straight line passing through the point \(\rm (x_1, y_1)\) is given by,
\(\rm (y – y_1) = m (x -x_1)\), where m is slope of the line.
The equation of straight line passing through the point (1, -2) is given by,
\(\rm (y + 2) = m (x -1)\) ….(1)
The equation of straight line passing through the point (1, -2) and parallel to the line y = 5x – 2
⇒ Slope of the line y = 5x – 2 is m = 5.
The slope of the parallel lines are equal.
So slope of the required line is m = 5
Equation (1) becomes
⇒ \(\rm (y + 2) = 5 (x -1)\)