The enthalpy of formation of ammonia is `-46.0 kJ mol^(-1)`. The enthalpy change for the reaction
`2NH_(3)(g)rarr2N_(2)(g)+3H_(2)(g)` is
A. 46.0 kJ `mol^(-1)`
B. `92.0 kJ mol^(-1)`
C. `-23.0 kJ mol^(-1)`
D. `-92.0 kJ mol^(-1)`
`2NH_(3)(g)rarr2N_(2)(g)+3H_(2)(g)` is
A. 46.0 kJ `mol^(-1)`
B. `92.0 kJ mol^(-1)`
C. `-23.0 kJ mol^(-1)`
D. `-92.0 kJ mol^(-1)`
Correct Answer – B