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Mahmood Rao Surana
Asked: 2022-11-07T01:55:04+05:30 In:

The enthalpy changes for the following process are listed below :
`Cl_(2)(g)=2Cl(g),” “242.3” kJ”mol^(-1)`
`I_(2)(g)=2I(g),” “151.0” kJ”mol^(-1)`
`ICl(g)=2I(g)+Cl(g),” “211.3” kJ”mol^(-1)`
`I_(2)(s)=I_(2)(g),” “62.76” kJ”mol^(-1)`
Given that standard states for iodine and chlorine are `I_(2)(s)` and `Cl_(2)(g)`, the standerd enthalpy of formation for ICl(g) is :
A. `-16.8 KJ mol^(-1)`
B. `+16.8 KJ mol^(-1)`
C. `+244.8 KJ mol^(-1)`
D. `-14.6 KJ mol^(-1)`

The enthalpy changes for the following process are listed below :
`Cl_(2)(g)=2Cl(g),” “242.3” kJ”mol^(-1)`
`I_(2)(g)=2I(g),” “151.0” kJ”mol^(-1)`
`ICl(g)=2I(g)+Cl(g),” “211.3” kJ”mol^(-1)`
`I_(2)(s)=I_(2)(g),” “62.76” kJ”mol^(-1)`
Given that standard states for iodine and chlorine are `I_(2)(s)` and `Cl_(2)(g)`, the standerd enthalpy of formation for ICl(g) is :
A. `-16.8 KJ mol^(-1)`
B. `+16.8 KJ mol^(-1)`
C. `+244.8 KJ mol^(-1)`
D. `-14.6 KJ mol^(-1)`
Parabola
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  1. Correct Answer – B
    `(1)/(2) I_(2)(s) + (1)/(2) CI_(2)(g) rarr ICI(g)`
    `DeltaH_(f,ICI) (g) = [(1)/(2)DeltaH_(I_(2))(s) rarr I_(2)(g) + (1)/(2)DeltaH_(I-I) + (1)/(2)Delta_(CI-CI)] – [DeltaH_(I-CI)]`
    `=[(1)/(2)xx 62.76 + (1)/(2)151.0 + (1)/(2)xx 242.3] -[211.3]=16.73 KJ//mol`

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Ghanshyam Boase
Asked: 2022-11-06T08:20:21+05:30 In:

The enthalpy changes for the following process are listed below :
`Cl_(2)(g)=2Cl(g),” “242.3” kJ”mol^(-1)`
`I_(2)(g)=2I(g),” “151.0” kJ”mol^(-1)`
`ICl(g)=2I(g)+Cl(g),” “211.3” kJ”mol^(-1)`
`I_(2)(s)=I_(2)(g),” “62.76” kJ”mol^(-1)`
Given that standard states for iodine and chlorine are `I_(2)(s)` and `Cl_(2)(g)`, the standerd enthalpy of formation for ICl(g) is :
A. `+16.8 kJ mol^(-1)`
B. `+244.8 kJ mol^(-1)`
C. `-14.6 kJ mol^(-1)`
D. `-16.8 kJ mol^(-1)`

The enthalpy changes for the following process are listed below :
`Cl_(2)(g)=2Cl(g),” “242.3” kJ”mol^(-1)`
`I_(2)(g)=2I(g),” “151.0” kJ”mol^(-1)`
`ICl(g)=2I(g)+Cl(g),” “211.3” kJ”mol^(-1)`
`I_(2)(s)=I_(2)(g),” “62.76” kJ”mol^(-1)`
Given that standard states for iodine and chlorine are `I_(2)(s)` and `Cl_(2)(g)`, the standerd enthalpy of formation for ICl(g) is :
A. `+16.8 kJ mol^(-1)`
B. `+244.8 kJ mol^(-1)`
C. `-14.6 kJ mol^(-1)`
D. `-16.8 kJ mol^(-1)`
Parabola
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  1. Correct Answer – A
    `1/2 I_(2)+1/2 Cl_(2) rarr ICl, DeltaH=H_(R)-H_(P)`

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Aatif Chaudhary
Asked: 2022-11-04T19:49:39+05:30 In:

The enthalpy changes for the following process are listed below :
`Cl_(2)(g)=2Cl(g),” “242.3” kJ”mol^(-1)`
`I_(2)(g)=2I(g),” “151.0” kJ”mol^(-1)`
`ICl(g)=2I(g)+Cl(g),” “211.3” kJ”mol^(-1)`
`I_(2)(s)=I_(2)(g),” “62.76” kJ”mol^(-1)`
Given that standard states for iodine and chlorine are `I_(2)(s)` and `Cl_(2)(g)`, the standerd enthalpy of formation for ICl(g) is :
A. `-16.8 kJ mol^(-1)`
B. `+16.8 kJ mol^(-1)`
C. `+244.8 kJ mol^(-1)`
D. `-14.6 kJ mol^(-1)`

The enthalpy changes for the following process are listed below :
`Cl_(2)(g)=2Cl(g),” “242.3” kJ”mol^(-1)`
`I_(2)(g)=2I(g),” “151.0” kJ”mol^(-1)`
`ICl(g)=2I(g)+Cl(g),” “211.3” kJ”mol^(-1)`
`I_(2)(s)=I_(2)(g),” “62.76” kJ”mol^(-1)`
Given that standard states for iodine and chlorine are `I_(2)(s)` and `Cl_(2)(g)`, the standerd enthalpy of formation for ICl(g) is :
A. `-16.8 kJ mol^(-1)`
B. `+16.8 kJ mol^(-1)`
C. `+244.8 kJ mol^(-1)`
D. `-14.6 kJ mol^(-1)`
Parabola
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  1. Correct Answer – B
    `(1)/(2)I_(2(g))+(1)/(2)Cl_(2(g))rarr ICl_((g)), Delta H_(f)(ICl) = ?`
    `eq.(v)=(1)/(2)[eq(i)+eq(ii)+eq(iv)]-eq(iii)`
    `Delta H=(1)/(2)[Delta H_(1)+Delta H_(2)+Delta H_(4)]-Delta H_(3)`

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