The enthalpy change when 1 L of 1 M `H _(2)SO_(4)` is completely neutralized by 1L of1 M `Ca(OH)_(2)` will be
A. `-13.7 kcal`
B. `-27.4 kcal`
C. `-1.37 kcal`
D. `- 2.74 kcal`
A. `-13.7 kcal`
B. `-27.4 kcal`
C. `-1.37 kcal`
D. `- 2.74 kcal`
Correct Answer – b
1 L of 1 M `H_(2)SO_(4)` gives 2 moles of`H^(+)` ions
1L of`M Ca9OH)_(2)` gives 2 moles of `OH^(-) ` ions
Hence, for complete neutralization of 2 molesof `H^(+)` ions by 2 molesof `OH^(-)` ions.
`DeltaH = 2 ( – 13.7) kcal =- 27.4 kcal`