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Riya Mistry
Asked: 2022-11-02T11:12:44+05:30 In:

the enthalpy change for the reaction C3H8 + H2 =C2H6 + CH4 at 25*c is 55.7 kj/mole Calculate the heat of combusition of C2H6 .the heat of combustion of H2.CH4,C[graphite] are -285.8   , -890.0 , -393.5 kj/mole respestevily . Heat of combustion of propani is -2240 kj/mole

the enthalpy change for the reaction C3H8 + H2 =C2H6 + CH4 at 25*c is 55.7 kj/mole Calculate the heat of combusition of C2H6 .the heat of combustion of H2.CH4,C[graphite] are -285.8   , -890.0 , -393.5 kj/mole respestevily . Heat of combustion of propani is -2240 kj/mole
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  1. Given

    C3H8 + H2 =C2H6 + CH4,           ΔH1= + 55.7 kJ/mole

    H2+1/2O2 =H2O,                      ΔH2= -285.8 kJ/mole

    CH4+2O2 =CO2+2H2O,           ΔH3= -890.0 kJ/mole

    C(graphite)+O2 =CO2,             ΔH4= -393.5 kJ/mole

    C3H8 +5 O2 =3 CO2+4H2O,    ΔH5=  -2240 kJ/mole

    we are to measure

    C2H6 +7/2 O2 =2CO2+3H2O,   ΔH6= ?  kJ/mole

    So

    ΔH6 = ΔH5– ΔH1 +   ΔH2 –   ΔH3

    = -2240– 55.7 +   (-285.8)  -(-890.0)

    = -1691.5 kJ/mole

     

     

     

     

     

     

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