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Lalit Dev Sharma
Asked: 2022-11-11T13:55:30+05:30 In:

The empirical formula and molecule mass of a compound are `CH_(2)O` and 180g respectivel. What will be the molecular formula of the compound?
A. `C_(9)H_(18)O_(9)`
B. `CH_(2)O`
C. `C_(6)H_(12)O_(6)`
D. `C_(2)H_(4)O_(2)`

The empirical formula and molecule mass of a compound are `CH_(2)O` and 180g respectivel. What will be the molecular formula of the compound?
A. `C_(9)H_(18)O_(9)`
B. `CH_(2)O`
C. `C_(6)H_(12)O_(6)`
D. `C_(2)H_(4)O_(2)`
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  1. Correct Answer – C

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Chand Chander
Asked: 2022-11-10T16:41:44+05:30 In:

The empirical formula and molecule mass of a compound are `CH_(2)O` and 180g respectivel. What will be the molecular formula of the compound?
A. `C_(9)H_(18)O_(9)`
B. `CH_(2)O`
C. `C_(6)H_(12)O_(6)`
D. `C_(2)H_(4)O_(2)`

The empirical formula and molecule mass of a compound are `CH_(2)O` and 180g respectivel. What will be the molecular formula of the compound?
A. `C_(9)H_(18)O_(9)`
B. `CH_(2)O`
C. `C_(6)H_(12)O_(6)`
D. `C_(2)H_(4)O_(2)`
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  1. Empirical formula mass `= CH_(2)O`
    `=12+2xx1+16=30`
    Molecular mass =180
    `n=(“Molecular mass”)/(“Empirical formula mass”)`
    `=(180)/(30)=6`
    `therefore` Molecular formula =nxx amp rical formula
    `=6xxCH_(2)O`
    `=C_(6)H_(12)O_(6)`

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