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Hina Qabeel Ghose
Asked: 2022-11-04T18:48:11+05:30 In:

The distance between the point of suspension and the centre of gravity of a compound pendulum is `l` and the radius of gyration about the horizontal axis through the centre of gravity is `k`, then its time period will be
A. `2pisqrt((l+k)/(g))`
B. `2pisqrt((l^(2)+k^(2))/(lg))`
C. `2pisqrt((l+k^(2))/(g))`
D. `2pisqrt((2k)/(lg))`

The distance between the point of suspension and the centre of gravity of a compound pendulum is `l` and the radius of gyration about the horizontal axis through the centre of gravity is `k`, then its time period will be
A. `2pisqrt((l+k)/(g))`
B. `2pisqrt((l^(2)+k^(2))/(lg))`
C. `2pisqrt((l+k^(2))/(g))`
D. `2pisqrt((2k)/(lg))`
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1 Answer

  1. Correct Answer – B
    `T = 2pisqrt((l)/(mgl)) = 2pisqrt((l^(2) + k^(2))/(gl))`

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