The different in the work done when one mole of `Al_(4)C_(3)(s)` reacts with water in a closed vesselat `27^(@)C` against atmospheric pressure and that in an open vessel under the same conditions is
A. greater in the open vessel by 600 cal
B. greater in the closed vessel by 600 cal
C. greater in the open vessel by 1800 cal
D. greater in the closed vessel by 1800cal
A. greater in the open vessel by 600 cal
B. greater in the closed vessel by 600 cal
C. greater in the open vessel by 1800 cal
D. greater in the closed vessel by 1800cal
Correct Answer – C
Reaction occuringis `:` `underset(1 mol)(Al_(4)C_(3) (s))+ 12 H_(2)O(l) rarr 4Al(OH)_(3) +underset(3 mol)(3CH_(4))`
When the vessel is closed,volume `=` constant , i.e., `DeltaV = 0`.Hence,`w=- PDeltaV =0`
When vessle is open, initial volume, `V_(1) =0` ( as no gas is present)
Final volume , `V_(2) = `Volume of3 mole of `CH_(4)`
`PV_(2) = nRT`
`:.V_(2)= (nRT)/(P)`
`:. w = – P(V_(2)-V_(1))= -PV_(2)`
`= – P xx(nRT)/(P) = – nRT`
`= – 3 xx 2 xx 300 = – 1800 cal`
i.e., work isdone by the system.