The difference of two natural no. Is 5. If the difference in their reciprocal is 1/10. Find the no.
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Let two numbers be x and y. So x-y= 5 …(1)1/y-1/x= 1/10x-y/xy = 1/105/xy = 1/10xy = 50From eq (1), we have x= 5+y(5+y)y = 50y2+5y = 50y2\xa0+5y -50=0y2\xa0+10y -5y -50=0y(y+10) -5(y+10) =0(y+10)(y-5) = 0y = 5 or -10y= 5 because -10 can not be a natural numberx = 5+5 =10One number is 5 and other number is 10.\xa0