The difference between `Delta H` and `Delta U` for the combustion of methane at `27^(@)C` will be (in `J mol^(-1)`)
A. `8.314 xx 27 xx – 3`
B. `8.314 xx 300 xx (-3)`
C. `8.314 xx 300 xx (-2)`
D. `8.314 xx 300 xx1`
A. `8.314 xx 27 xx – 3`
B. `8.314 xx 300 xx (-3)`
C. `8.314 xx 300 xx (-2)`
D. `8.314 xx 300 xx1`
Correct Answer – C
Thermochemical equaiton for the combustion of methane is
`CH_(4) (g) + 2 O_(g) rarr CO_(2) (g) + 2H_(2) O (1)`
According to thermodynamics,
`Delta H = Delta U + Delta n_(g) RT`
or `Delta H – Delta U = Delta n_(g) RT`
Where `Delta n_(g) = sum n_(P) (g) – sum n_(R ) (g)`
`= (1) – (1 + 2)`
`= – 2`
`:. Delta – Delta U = (-2) (8.314) (300)`