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Richa Kaul
Asked: 2022-11-09T22:18:24+05:30 In:

The decreasing order of the boiling points of the following hydrides
(i) `NH_3` (ii) `PH_3`
(iii) `AsH_3` (iv) `SbH_3`
(v) `H_2O` is
A. VgtIVgtIgtIIIgtII
B. VgtIgtIIgtIIIgtIV
C. IgtIVgtIIIgtIIgtV
D. IVgtIIIgtIgtIIgtV

The decreasing order of the boiling points of the following hydrides
(i) `NH_3` (ii) `PH_3`
(iii) `AsH_3` (iv) `SbH_3`
(v) `H_2O` is
A. VgtIVgtIgtIIIgtII
B. VgtIgtIIgtIIIgtIV
C. IgtIVgtIIIgtIIgtV
D. IVgtIIIgtIgtIIgtV
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  1. Correct Answer – A
    The b.pt of `SbH_(3)` is higher than that of `NH_(3)`. The reason being that the stronger van der walls forces of attraction more than compensate the rease in b.pt of `NH_(3)` due to H-bonding (A ) is correct.

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